How to I go about solving this question? given that the answer is in polar form

z+3−i = 4z+9−19i,

where (z+3-i) is a conjugate

Question

How to I go about solving this question? given that the answer is in polar form

z+3−i = 4z+9−19i,

where (z+3-i) is a conjugate

directrix · Answer

@ineedhelpwithmatrices   What are the instructions for this problem as given in your text?

anonymous · Answer

@Directrix, the instructions are "Solve for z, and give your answer in the form a+bi."

anonymous · Answer

Just solve for z like you would a normal linear equation.
Get all of your z's on one side and everything else on the other

z+3−i = 4z+9−19i
-3z = -3 -9 + i - 19i
-3z = -12 - 18i
now divide both sides by -3
z = -12/-3 - 18i/-3
  = 4 + 6i

anonymous · Answer

but don't you have to find the following conjugate of z+3-i? @BangkokGarrett

anonymous · Answer

Are you supposed to solve for z? If so, that's what I've done.
I don't see what a conjugate has anything to do with solving for z here.

anonymous · Answer

Conjugates are usually used for dealing with imaginary numbers in the denominator of a fraction.

anonymous · Answer

well the first eqn looks like this: |dw:1383416187722:dw|

anonymous · Answer

what? you don't have ANY fractions like that in your original posting.

anonymous · Answer

You're mixed up on terminology.
The CONJUGATE of 2 - i is 2 + i
The CONJUGATE of 5 + 3i is 5 - 3i

anonymous · Answer

My bad

anonymous · Answer

So, I have no idea what your question is. What exactly is the equation given and the instructions?

anonymous · Answer

|dw:1383416431329:dw|