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Write the equation of the line parallel to the line 4x + 2y = 5 and passing through the point (-3,5). 2y/2 -4x/2 +5/2 m=2 y=-4x+20 ?
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@agent0smith
4x + 2y = 5 i think your slope is wrong... subtract 4x on both sides: 2y = -4x + 5 divide everything by 2: y = -2x+5 so your slope is m=-2, for a parallel line. Now use point-slope form again, y-y1 = m(x-x1) with the point (-3,5)
y-5=-2x+6 then -5 on both sides y=-2x+1
very good! but i think you missed a negative... y-5 = -2(x-(-3))
oh yeah lol, y=-2x-1
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:D
I have on now with perpendicular, would I do the same steps?
basically BUT remember you have to get the negative reciprocal of the original line's slope.
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