how to get inverse laplace transform of this equation s^2+ squrt 2s + 1

Question

how to get inverse laplace transform of this equation   s^2+ squrt 2s + 1

anonymous · Answer

is it...
$$s ^{2} +\sqrt{2s} + 1$$

anonymous · Answer

yes the whole equation in denominator

anonymous · Answer

$$\sqrt{2} e^{-t/\sqrt{2}} \sin (t/\sqrt{2})$$ this is ans but i want explanation of middle steps shortly

anonymous · Answer

i'm still working on simplifying the equation... :)

anonymous · Answer

isn't it...
$$\frac{ 1 }{ s ^{2} + \sqrt{2} s + 1 } ?$$

anonymous · Answer

yes

anonymous · Answer

i think i hav to remember all  laplace transform formulae

Thanks for u r effort

what s u r profession ....?

anonymous · Answer

i'm an electronics engineer by profession...

anonymous · Answer

sorry i was not able to finish your problem... got busy this day in my work... by the way... it's really the table such as...
$$L ^{-1}\left\{ \frac{ a }{ (s ^{2}+a ^{2}) } \right\}=\sin at$$

anonymous · Answer

another is...
$$L ^{-1}\left\{ \frac{ 1 }{ (s+a) } \right\}=e ^{-at}$$