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can someone please check my work
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find the dericative vales of \[\sqrt{x+5}\] \[1/x^2 +49 \] and x^2 - 16 I got 1/2sqrt x 2x and 2x
i mean (1/x^2 + 49)
Are these 3 separate questions?
yes
Derivative of y = (x+5)^(1/2) is (1/2)(x+5)^(-1/2) or can be written as 1/(2sqrt(x+5))
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The derivative of 1/(x^2+49) is (-2x/(x^2+49)^2)
Derivative of x^2 + 16 is just 2x.
Your second problem is (1/x^2) + 49?
I took the derivative of 1/(x^2+49)
thank you
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