Evaluate ∫(0,2)∫(x,2) (xsqt(1+y^3)) dy dx... Its supposed to be easier by changing the order but i dont know how
\[\Large \int\limits_{x=0}^2\quad\int\limits_{y=x}^2\;x\sqrt{1+y^3}\;dy\;dx\]So let's start by drawing the region we're integrating over in x and y:
|dw:1383516751658:dw|Understand how I drew the region?
yes, i do
|dw:1383520028797:dw|So to reverse them we would ummm..
|dw:1383520119372:dw|
and in the x direction instead of x varying between constants,|dw:1383520170074:dw|
|dw:1383520191697:dw|
I can't think of the right words to explain this.. grrr. Hopefully the pictures help a little bit :c
\[\Large \int\limits\limits_{x=0}^2\quad\int\limits\limits_{y=x}^2\;x\sqrt{1+y^3}\;dy\;dx\qquad\to\qquad\int\limits\limits_{y=0}^2\quad\int\limits\limits_{x=0}^y\;x\sqrt{1+y^3}\;dx\;dy\]
Oh, Okay. I understand what you did. The second graph was basically a rectangle to see where it starts and ends. Thank You!!!
yay \c:/
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