Question

sin^2x+cosx
0 12 years ago

Answer 1

Wait! Do you have to find the derivative first?
cos^2x-sinx

Answer 2

For critical numbers, begin by differentiating, to obtain 2sin(x)*cos(x)-sin(x)=0 solve for x.

Answer 3

2sin(pi)*cos(pi)-sin(pi)=0?

Answer 4

yes, sin(pi)=0 so 2sin(pi)cos(pi)-sin(pi)=0, but 0 isn't within the bounds try x=1.04.

Answer 5

more accurately x= 1.047197

Answer 6

2sin(pi/3)cos(pi/3)-sin(pi/3)=0

Answer 7

2sin(5pi/3)cos(5pi/3)-sin(5pi/3)=0