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Mathematics 25 Online
OpenStudy (anonymous):

PLEASE HELP ME!! Simplify the given expression. square root of negative 49 over open parentheses 3 plus 4 I close parentheses minus open parentheses 2 minus 5 i

OpenStudy (anonymous):

" square root of negative 49"? A negative number can not be square rooted.

OpenStudy (anonymous):

\[\sqrt{-49}\over \left( 3+4i \right)-\left( 2-5i \right)\] @ColossalMagnitude

OpenStudy (anonymous):

Oh, you're dealing with imaginary numbers, okay, that makes sense now. Just wait a minute and let me figure it out first, then I'll explain it to you.

OpenStudy (anonymous):

ok thank you @ColossalMagnitude

OpenStudy (anonymous):

Numerator would simplify to 7i because you can rewrite √-49 as √49√-1, which is equal to 7i. So, so far, we have: \[\frac{ 7i }{ (3+4i)-(2-5i) }\]

OpenStudy (anonymous):

We can simplify - (2 - 5i) to (-2 + 5i), so the denominator turns into: \[\frac{ 7i }{ (3 + 4i) + (-2 + 5i) }\]

OpenStudy (anonymous):

We can easily simplify that to: \[\frac{ 7i }{ 9i + 1 }\]

OpenStudy (anonymous):

how did you get from (3+4i)+(-2+5i) to (9i+1) @ColossalMagnitude

OpenStudy (anonymous):

You can simplify (3+4i)+(-2+5i) to 3 + 4i - 2 + 5i. You know how I got 9i + 1 now?

OpenStudy (anonymous):

quantity 7 plus 7i over 2 quantity 63 plus 7i over 82 quantity negative 7 plus 7i over 2 negative 63 plus 7 I over 82 these are the answers

OpenStudy (anonymous):

Ummm ... wait a second, let me think for a bit.

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

Okay, I got it. First, we want to rationalize the denominator. To do this, we would have to multiply the numerator and denominator by (9i - 1) \[\frac{ 7i(9i - 1) }{ 9i + 1(9i-1) }\]

OpenStudy (anonymous):

okay so far that makes sense

OpenStudy (anonymous):

Then, we have to simplify: \[\frac{ 7i(9i - 1) }{ -81 - 9i + 9i - 1}=\frac{ 7i(9i - 1) }{ -82 }\]

OpenStudy (anonymous):

Make sense?

OpenStudy (anonymous):

wouldnt you distrube the numerator

OpenStudy (anonymous):

Not yet. But do you understand how I simplified the denominator?

OpenStudy (anonymous):

it would be 63i-63 or am i wrong

OpenStudy (anonymous):

oh yes i understand

OpenStudy (anonymous):

Okay, good. Now for the numerator: \[\frac{ 7i(9i - 1) }{ -82 } =\frac{ (7 * 9 * i^2) - 7i }{ -82 } = \frac{ (63 * -1) - 7i }{ -82 } = \frac{ -63 - 7i }{ -82 }\]

OpenStudy (anonymous):

You can also simplify that to: \[\frac{ -(63 + 7i) }{ -(82) } = \frac{ 63 + 7i }{ 82 }\]

OpenStudy (anonymous):

wouldnt it be -63 + 7i?

OpenStudy (anonymous):

You are cancelling out the negative on the numerator and the denominator, so you would just be left with what's inside the parentheses, which is (63 + 7i) / (82). So it would be this one "quantity 63 plus 7i over 82". Make sense?

OpenStudy (anonymous):

Hello? You still there?

OpenStudy (anonymous):

sorry im here @ColossalMagnitude

OpenStudy (anonymous):

i understand now i wanted make sure i understoof everything

OpenStudy (anonymous):

Okay, good, good luck with the rest of your homework/test/etc. Also, a medal would be nice if you are satisfied with my answer :).

OpenStudy (anonymous):

lol alright thank you

OpenStudy (anonymous):

Welcome :). Bye.

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