find lim as x approaches pi/4: (1-tanx)/(sinx-cosx)
it is in 0/0 form so we have to use l hospitals rule
do u know abt l hospital rule?
we did like one in class but i don't know how to use it well yet
ok u r given limit x tends to pi/4 so first step is to put pi/4 in the given eqn in place of x.first check numerator wat u get by putting it.
can u tell me wt will u get when u put pi/4 in place of x in numerator?
well it's 0 over 0 so we need to change it
i just haven't done limits in ages and i don't remember
have u undrstood how it is coming 0/0?
yes
Why not change tan x to sin x/cos x ...and simplify the expression? Then take the limit.
ok then,the next step is to differentiate numerator separety
its ur choice @Spidermonkeyy but u should also learn l hospitals rule.
i fu wnt i an explain the entire process to u.
differentiate as in -sec^2x?
yes please
yes good! now differentiate denominator and tell me wt u get
cos+sin?
yes good! now put the differentiated part in fraction
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