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Mathematics 18 Online
OpenStudy (anonymous):

find lim as x approaches pi/4: (1-tanx)/(sinx-cosx)

OpenStudy (anonymous):

it is in 0/0 form so we have to use l hospitals rule

OpenStudy (anonymous):

do u know abt l hospital rule?

OpenStudy (anonymous):

we did like one in class but i don't know how to use it well yet

OpenStudy (anonymous):

ok u r given limit x tends to pi/4 so first step is to put pi/4 in the given eqn in place of x.first check numerator wat u get by putting it.

OpenStudy (anonymous):

can u tell me wt will u get when u put pi/4 in place of x in numerator?

OpenStudy (anonymous):

well it's 0 over 0 so we need to change it

OpenStudy (anonymous):

i just haven't done limits in ages and i don't remember

OpenStudy (anonymous):

have u undrstood how it is coming 0/0?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

Why not change tan x to sin x/cos x ...and simplify the expression? Then take the limit.

OpenStudy (anonymous):

ok then,the next step is to differentiate numerator separety

OpenStudy (anonymous):

its ur choice @Spidermonkeyy but u should also learn l hospitals rule.

OpenStudy (anonymous):

i fu wnt i an explain the entire process to u.

OpenStudy (anonymous):

differentiate as in -sec^2x?

OpenStudy (anonymous):

yes please

OpenStudy (anonymous):

yes good! now differentiate denominator and tell me wt u get

OpenStudy (anonymous):

cos+sin?

OpenStudy (anonymous):

yes good! now put the differentiated part in fraction

OpenStudy (anonymous):

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