Question

area of triangle formed by the lines y=ax, x+y=a and the y axis is equal to

Answer 1

first find the dots where the lines meet. so that would be..
x+y=a is equal to y=-x+a,so
-x+a=ax
(a+1)x=a
x=a/a+1
y=ax simply pass (0.0), and x+y=a pass a, so S= a*a/a+1*1/2

Answer 2

hope it helped :)

Answer 3

y=ax, --------(1
x+y=a---------(2

from (1 and (2 we have
x+ax=a
x(1+a) = a
\[x = \frac{a}{1+a}\]
therefore
y= ax
i.e. \[y=a \times \frac{a}{1+a}\]
\[\rightarrow y= \frac{a^2}{1+a}\]
let x = base and y = height of the riangle.
\[Area -of -\triangle = \frac{1}{2} \times base \times height\]
\[\rightarrow Area -of -\triangle = \frac{1}{2} \times \frac{a}{1+a} \times \frac{a^2}{1+a}\]
\[\Huge \rightarrow Area -of -\triangle = \frac{a^3}{2(1+a)^2} \]
is the required answer of the area of the triangle.
@HARSH123

Answer 4

@HARSH123

Answer 5

sorry but ur answer is wrong jh3power is right

Answer 6

@HARSH123 What is your answer?

Answer 7

@HARSH123

Answer 8

a^2/2|1+a|