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Given that f(x) = 2x + 1 and g(x) = the quantity of 3x minus 1, divided by 2 solve for g(f(3)). 5 7 9 10
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take f(x) and substitute it for x in g(x) i.e. for every x in g(x) use 2x+1 in it's place
would it be 7?
checking
10 i think so
sorry had to let the dog out
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substitute 3 for x in f(x) and solve, use that to replace x in g(x) and solve, 7 is not correct
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