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OpenStudy (anonymous):
is it -3 times 2 or are you saying -3x?
OpenStudy (anonymous):
it is \[-3x ^{2}\]
OpenStudy (anonymous):
ok give me one min ill solve the problem
OpenStudy (anonymous):
ok thanks.all i know of it is it is going to be a complex number solution
OpenStudy (anonymous):
ok so what I got was 9x but im really not sure ill try to show you the steps one sec
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OpenStudy (anonymous):
ok thanks
OpenStudy (anonymous):
wait wait wait im wrong
OpenStudy (anonymous):
ill redo do it sorry
OpenStudy (anonymous):
it ok man it confuses the crap outa me.
OpenStudy (anonymous):
ok lets try to do it together
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OpenStudy (anonymous):
ok
OpenStudy (anonymous):
-3x is squared making it 9x right?
OpenStudy (anonymous):
right
OpenStudy (anonymous):
ok so then 9x - 4x is 5x
OpenStudy (anonymous):
then you are left with 4 or 4x
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OpenStudy (anonymous):
i think
OpenStudy (anonymous):
what grade is this for?
OpenStudy (anonymous):
hello
OpenStudy (anonymous):
?
OpenStudy (anonymous):
sorry i was away from keyboard.it is 10th grade algebra 2
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OpenStudy (anonymous):
oh wow haha im only in 8th grade
OpenStudy (anonymous):
well sorry that i couldn't be much help
OpenStudy (anonymous):
lmfao XD
OpenStudy (anonymous):
sorry :(
OpenStudy (anonymous):
it ok dude
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OpenStudy (anonymous):
use the quadratic formula:
\[\frac{ 4 \pm \sqrt{(-4)^2-4(-3)(-4)} }{ 2(-3) }\]
reduces to:
\[\frac{ 4 \pm \sqrt{-32} }{ -6 }\]
since you cannot take the square root of a negative you insert i.
\[x =\frac{ 4 + \sqrt{32}i }{ -6 }\]
AND
\[x =\frac{ 4 - \sqrt{32}i }{ -6 }\]