Find f(g(x)) If g(x) = 2x^2 + 4 and f(x)= x-2/4
I'm in calculus and I'm learning this right now too. You have to use chain rule, which means first you take the derivative of g(x) and then multiple by the derivative of f(x). Would you like me to show you?
yes!
hold on one second, I'll work it out on paper and then type it for you
is that x minuts two all over four?
yep over 4
the first step is to use the quotient rule, would you like me to explain that?
Yes
so my teacher taught us a catchy phrase to remember quotient rule, it's... (d means derivative). low is the numerator and high is the denomanator low*d high minus high*d low all over low squared and there you go. in this case that would mean you take the quotient rule of f(x)... 4*1-(x-2)0 all over 4^2
this would give you zero, so I'm not sure if that would be correct, because then you are supposed to insert g(x) in all the places there is an x and multiple by the derivative of g(x). this would mean the whole answer is 0, but that sounds like it may not be correct
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