Question

1. what is the polynomial function in standard form with zeroes 1,2,-2, and -3
A x^2+2x^3+7x^2-8x+12
B. X^4+2x^3-7x^2-8x+12
C. X^4+2x^3-7x^2+8x+12
D. x^4+2x^3+7x^2+8x+12
2. what are the zeroes of the function? what are their multiplicities?
f(x)=5x^3-5x^2-30x
A. the number 3,-2,and 0 are zeros of multiplicity 1
B. The numbers 3,-2, and 0 are zeros of multiplicity 2
C. the numbers -3 , 2, and 0 are zeroes of multiplicity 1
D. the numbers -3,2, and 0 are zeros of multiplicity 2
3 divid -3x^3-4x^2+4x+3 by x-2
A. -3+- 5i,-4
B. 3+- 5i,-4
C. -3+-i,4
D. 3+-i,4
4. one zero of f(x)=x^3+2x^3-5x-6 is 2. what are the other zeroes of the function
A. 1 and 3
B. -1 and -3
C. 2 and -3
D. 2 and 3

5.what is the second term of (s+v)^5?
A. 25s^4
B. 25s^4v
C. 5s^4v
D. 125s^4v

Answer 1

@kelliegirl33 @Lukecrayonz @ladydeadpool @austinL @Coolsector @charlotte123 @Jemurray3 @pianoem328 @insanitycat @charlotte123 anyone help ?

Answer 2

1. what is the polynomial function in standard form with zeroes 1,2,-2, and -3
A x^2+2x^3+7x^2-8x+12
B. X^4+2x^3-7x^2-8x+12
C. X^4+2x^3-7x^2+8x+12
D. x^4+2x^3+7x^2+8x+12

well if we have the zeros we know the factored form of this equation is
(x-1)(x-2)(x+2)(x+3) and we can eliminate A since the the equation will have a degree of 4

Answer 3

so distribute the factored form of (x-1)(x-2)(x+2)(x+3)
and theres your equation