Question

3tan^2*X+cot^2*X=4 X= ??

Answer 1

Make the substitution cot(X) = 1/tan(X), multiply throughout by tan^2(X).
Let y = tan^2(X). You will get a quadratic equation in y. Solve for y and then put back y = tan^2(X) and solve for X.

Answer 2

you can show me more? im stuck

Answer 3

3tan^2*X + cot^2*X = 4
cot(X) = 1/tan(X)
3tan^2(X)+1/tan^2(X) = 4
Multiply throughout by tan^2(X)
3tan^4(X) + 1 = 4tan^2(X)
3tan^4(X) - 4tan^2(X) + 1 = 0
Let y = tan^2(X)
3y^2 - 4y + 1 = 0

Solve the quadratic equation for y.

Answer 4

thanks man!

Answer 5

After you solve for y, remember to replace y by tan^2(X) and solve for X.

You are welcome.