Write each expression in terms of sin(theta), cos(theta), or both. Simplify wherever possible. Its trig identities 1. tan(theta) * csc(theta) = ??? 2. tan(theta) / sec(theta) = ???
I know what the identities are I just don't know how to solve the problem
\(\bf tan(\theta)\cdot csc(\theta)\implies \cfrac{\cancel{sin(\theta)}}{cos(\theta)}\cdot \cfrac{1}{\cancel{sin(\theta)}}\)
so its \[1 / \cos(\theta)\] ?
yes, and what's \(\bf \cfrac{1}{cos(\theta)} \quad ?\)
or sec(theta)
yeap
but is that still in terms of sin or cos (theta) ??
hmmm ohhh yeah... forgot that part... so ... .leave it like \(\bf \cfrac{1}{cos(\theta)}\) then
okay thanks a lot
\(\bf \cfrac{tan(\theta)}{sec(\theta)}\implies \cfrac{ \frac{sin(\theta)}{cos(\theta)} }{ \frac{1}{cos(\theta)} }\implies \cfrac{sin(\theta)}{\cancel{cos(\theta)}} \cdot \cfrac{\cancel{cos(\theta)}}{1}\)
yw
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