Question

A point on the rim of a .2m radius rotating wheel has a centripetal acceleration of 4m/s^2. What is the angular velocity of a point .10 m from the center of the wheel?

Answer 1

good problem! Well first, what's the formula for centripetal aceleration?

Answer 2

ok so Ac = v^2/r=rw^2

Answer 3

yah, so you can plug in

\[ 4 \ m/s^2 = (.2 \ m) \ \omega^2 \]
to find omega^2

Answer 4

so 4/.2=w^2 =>20 =w^2

Answer 5

\[4.5rad/s^2\]

Answer 6

So that's your omega, yah? The angular velocity

Answer 7

sweet thanks

Answer 8

Welcome ^_^ - and you know that for any pint on the wheel omeega is the same, yah? It's the magic of radians!

Answer 9

ok cool ill keep that in mind.

Answer 10

^_^