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Lim x^n
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Can you be a little more specific?
we won't get any indeterminate form, whatever x or n will tend to.... so, whatever 'x' or 'n' tends to , just plug in it as its value. like if x->0, just put x=0 in x^n to get the limit value =0
and yes, you need to tell what x tends to or n tends to, please post the entire question next time.
For 0<x<1, prove that lim x^n =0
lim n->infinity ?
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Yes, lim n goes to infinity
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