Question

A bullet moving at 500 m/s has a kinetic energy of 2500 J and a potential energy of 0.50 at a certain moment. What is the bullet's mass and how high above the ground is it at the moment?

Answer 1

Hello.

First, let's start with what we have.
v = 500 m/s
k = 2500 J
U = 0.50 J
\[k = \frac{ 1 }{ 2 }m v^{2}\]
\[U = mgh\]
To get the mass (m), just use the first equation, since you already have k and v.
To get it's height above the surface (h), just use the second equation, since you already have U and m. g is the earth gravitational constant 9.8 m/s^2.

Answer 2

Ok. Thanks!

Answer 3

the formula for finding the mass would be m=2k/v^2 ?

Answer 4

Yes.

Answer 5

and h=U/mg ?

Answer 6

Yes.