The speed of a pendulum is 0.91 C and its time period is 1.8 sec. Then what will be its period in initial frame. A. 2 s B. 1.62 s C. 1.60 s D. 1.58 s
@Mashy
my goodness are you dealing with special with relativity?
special relativity
No idea :(
@AllTehMaffs
what do u mean no idea? u just typed 0.91 C.. i hate 0.91Cs C = speed of light right?
Ops Sorry . I though u r asking Anyways yeah its C
Speed of light
so you are taking course on special relativity?!
yeah
hooray relativistic maths!
not my forte.. !! see you :P
its ok @Mashy
\[\Delta T' = DeltaT / \sqrt{1-v ^{2}/c ^{2}}\]
Am I right @AllTehMaffs ?
In the inertial frame its time will be dilated, so its time should be longer methinks - 2's the only answer that's bigger. We can check though! \[ \Delta t_{inertial} = \gamma \Delta t_{pendulum}\] which is your t' and t?
\[ \gamma=\frac{1}{\sqrt{1-\frac{v^2}{c^2}}}\]
t' is time dilated and t is time at rest
And time "at rest" is the time in the frame of the pendulum, yah?
yes
then yooz right! although I'm getting the wrong answer with it :/
which one is correct ?
oo.. its that simple? :D.. i thought that equation only worked for relativistic masses :D
time dilation and length contraction, too ^_^ All derived from the same 4-space vector
err, opposite for length contraction
oh i ll be darned!
I still dunno why the answer it's giving isn't right though :/ Are you sure it was .91c?
we have to find period in initial frame . Is it Delta T ?
.74 sec is mine answer ..
I got 4.3 sec....
t = time observed in the other reference frame t0 = time in observers own frame of reference (rest time) v = the speed of the moving object c = the speed of light in a vacuum
yahyah, and the speeds are all given in the frame of the pendulum, right? I mean, even if they weren't, there's no combination of those numbers that gives any of those answers...
|dw:1383851913820:dw|
Join our real-time social learning platform and learn together with your friends!