Question

Rewrite in vertex form y=x^2+14x+50

Answer 1

x = 7.
my guess but idk

Answer 2

idk really know but, that just a guess :)

Answer 3

Vertex: (−7,1)

Answer 4

let me explain the process.

Answer 5

The general form of the quadratic function is f(x) =ax2 + bx + c.
To convert the standard form(y = ax2 + bx + c) of a function into vertex form(y = a(x - h)2 + k), we have to write the equation in the complete square form and vertex(h, k) is given by:
h = −b2a
k = c - b24a


just gotta plug it in and you get

(-7,1)

Answer 6

since There is no A you would use one, since there is always a 1 in front of something when you don't see it

Answer 7

Ok so when i used the formula \[y=a(x-h)^2+k\] I got \[y=14(x-x)^2+50\]

Answer 8

is that correct when rewriting it in vertex form?

Answer 9

@cantthink96

Answer 10

i'm ever so sorry i didn't realize thats what the question was

Answer 11

you're going to need to find h and k before you can put it in vertex fom

Answer 12

Yeh so did I do it right by rewriting it that way?

Answer 13

ok thanks

Answer 14

h(x-coordinate) = −b2a
k(y - coordinate) = c - b24a

Answer 15

Ok thank you for the help!

Answer 16

hold on its -b/2a and c- b^2/4a