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evaluate the integral
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\[\int\limits_{?}^{?} \frac{ 3x dx }{\sqrt{4x^2+5} }\]
u=4x^2+5.
du=8x dx
and...?
rewrite the integral in terms of u and du. integral(3x dx/sqrt(4x^2+5))=integral(3x dx/sqrt(u)). since du=8x dx, dx=du/8x. integral(3x dx/sqrt(u))=integral(3/(8*sqrt(u)) du)=3sqrt(u)/4=3sqrt(4x^2+5)/4
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