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Mathematics 13 Online
OpenStudy (anonymous):

Help! Medal Awarded! (Attached file)

OpenStudy (anonymous):

hartnn (hartnn):

do you know how to find the domain ?

OpenStudy (anonymous):

no

hartnn (hartnn):

the quantity under sqrt \(\sqrt {..}\) cannot be negative, so what does x+10 > 0 give you ?

OpenStudy (anonymous):

x>-10

hartnn (hartnn):

yeah, and x cannot be -10 too because that will make denominator = 0 which is not allowed and x>-10 just means the domain is \(\large (-10,\infty )\) got this ?

OpenStudy (anonymous):

yes

hartnn (hartnn):

what about the range ? know how to find ?

OpenStudy (anonymous):

no

hartnn (hartnn):

the squar root can not yeild negative values so the range will be all positive values which is \((0,\infty )\)

OpenStudy (anonymous):

ok, thank you!

hartnn (hartnn):

welcome ^_^

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