Does anyone know how to find the derivative of f(x)=(sqrt(1/x^7)) the square root over the whole thing is confusing me
do you know the derivative of x^n ?
no I dont think so
\(\large \dfrac{d}{dx}x^n=n \times x^{n-1}\)
well I know that if the square root wasnt over the whole problem, then wouldn't the answer be -7/x^6? I just am confused on the square root being over the whole thing
how did u get -7/x^6 ?
\(\huge \sqrt A = A^{\frac{1}{2}}\)
\[\sqrt{(1)/(x^7)}\]
so if the square root wasnt there wouldnt the answer be -7x^-6?
i mean you have used the formula that i gave you to find derivative of x^7 , right ? but since we have square root, it'll be \(\large x^{7/2}\)
in the denominator
so, basically you are differentiating, 1/x^(7/2) or \(\large x^{-7/2}\)
thats the answer? I'm sorry I'm just confused lol
thats what you will be differentiating. what will u take 'n' as ?
so it'd be -7/2x^-4.5?
\[-7/2x^9/2\]
yes! but keep -9/2 as it is not 4.5
Thank you so much! :)
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Okay thanks again! :)
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