HELP ME? Show me how to do the work also - Calculate the speed of an 8.0 x 10^4 kg airliner with a kinetic energy of 1.1 x 10^9 J.
Above my pay grade, but don't you need a drag coefficient and altitude/atmospheric pressure to calculate this? They both effect speed.
Or is this equation, "static in a vacuum"
we are assuming no external forces. let K = kinetic energy, m = mass, V = velocity/speed \[K = \frac{ 1 }{ 2 }m V^2\] \[1.1 * 10^9 = \frac{ 1 }{ 2 }8.0*10^4* V^2\] solve for V
I got this \[1.1 x 10^9 = 1/2*8.0*10^4\] \[1100000000=0.5*8000\] \[1100000000 = 4000\] \[524.4 \] Did I do this right? Answers say its 1.7 x 10^2? Am I right?
i get 1.658* 10^2
\[V = \sqrt{\frac{ 1,100,000,000 }{ 0.5*80,000 }} = \sqrt{27500}\] but you should really enter 1.1 E 9 in your calculator (1.1 * 10^9) if you can't find the button, i can help.
Thank you, I understand now(: Could you help me with another problem?
ya
What is the speed of a 0.145 kg baseball if the kinetic energy is 109 J? I used the same equation and got 31.61 . I think I made a mistake. Answers say 38.8
i get 38.77 \[K = \frac{ 1 }{ 2 }m V^2\] \[V = \sqrt{\frac{ 2K }{ m }} = \sqrt{\frac{ 2*109 }{ 0.145 }}\]
How did you get the 2K? Thats the part I don't understand?
i'm just isolating V from:\[K = \frac{ 1 }{ 2 }m V^2\] multiply both sides by 2:\[2K = mV^2\]divide both sides by m\[\frac{ 2K }{ m } = V^2\]
what level calc is this problem from? wondering when I can look forward to these equations.
he multiplied both sides by 2 to clear the fraction
this equation is from mechanics or general physics. you will most likely be taking this class in the same time as cal 1
I can't take physics or mech until concurrent with calc 2
that is different that here ^_^. probably means you will be going straight into applying integration to basic physics. early physics classes here don't require calculus
I need help with two more problems if thats okay?
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