can anyone help plz
Place a penny on each vertex of the polygon(9 PENNYS). Take turns removing one penny or two pennies from adjacent vertices. The player who picks up the last coin(s) is the winner. TELL WEATHER ITS TRUE OR FALSE WHY Connor: If the first player removes one penny, I’ll visualize the line of symmetry containing the “empty” vertex and remove the two adjacent pennies on opposite sides of the symmetry line. If the first player removes two pennies on the first move, then I’ll visualize the line of symmetry between the two empty vertices and remove the penny on the symmetry line. This strategy will always leave three pennies on each side of the symmetry line after we each make our first move. After that, I’ll match each play the first player makes by choosing the mirror image. So, I’ll be able to remove the final coin(s)
@skullpatrol thanks for your help!
Are you convinced, there will be 3 pennies on either side of line-of-symmetry, after each makes their first move ?
so is this strategy true or not? @ganeshie8
@Chineseboy15 can u help if u are a lifesaver?
well the question is not just asking if its true or not. the question is asking, if its true why its true; and if its false, why its false
you will have to take it step by step and convince urself if it works always
ya thats right @ganeshie8
can u try, and answer my question above (my first reply)
Sorry, I cannot open your attachment, sanra123.
@Chineseboy15 here
im convinced
and we assume that the strategy is only for Nonagon; we dont care about other polygons
ok..
true
good, so we're left wid 3 pennies on either side of the line-of-symmetry.
true..
lets talk about second move now
ok
second move : the first player has two choices : he can take two ADJACENT pennies, or just one penny
yes thats true
@ganeshie8 ? are u there
@Chineseboy15 i posted it can u help
Place a penny on each vertex of the polygon(9 PENNYS). Take turns removing one penny or two pennies from adjacent vertices. The player who picks up the last coin(s) is the winner. TELL WEATHER ITS TRUE OR FALSE WHY Connor: If the first player removes one penny, I’ll visualize the line of symmetry containing the “empty” vertex and remove the two adjacent pennies on opposite sides of the symmetry line. If the first player removes two pennies on the first move, then I’ll visualize the line of symmetry between the two empty vertices and remove the penny on the symmetry line. This strategy will always leave three pennies on each side of the symmetry line after we each make our first move. After that, I’ll match each play the first player makes by choosing the mirror image. So, I’ll be able to remove the final coin(s)
I will try.
kk
Let us play this game, all right?
kk
9 coins
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u
sorry was on phone, can we finish now ?
okk lets finish
now as u said he will have 2 choices
Continued... that means : In second move, the First player can only take two pennies from ONLY ONE SIDE
yes
if he takes two pennies, he CANNOT take them from opposite sides of line of symmetry. (WHY ? )
there will be space
right?
Exactly ! there will be space, and the pennies on opposite sides are NEVER adjacent... Cuz, he broke it in the first move... he divided the pennies into two groups... both are disconnected
ya now i get it
So, on second move : IF the first player takes 2 pennies on one side, the second player can take 2 pennies on opposite side
so now how will we write it false, because...................
After second move, there will be two pennies left, one on each side of line-of-symmetry
wat happens during third move ?
each one takes 1 penny?
whi is the winner ?
*who
why ? u forgot the rules it seems
whoever takes the LAST penny is the winner
ohhhh right sorry!
Sorry, my computer lost the connection.
now.. the strategy is false,.........................
right?
the second player always has the tempo he is forcing the first player to leave one penny in the end.
second player is always winning, by this strategy. so... ?
id leave the conclusion to you, you may have to go through this exercise again to *see* why the second player always wins if he sticks to this strategy.
I have said that we can play this game.
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