Question

limit of the funtion :-
{[(2^n)+ 1][(7^n)+(10^n)]}^(1/n)
as n tends to infinity

Answer 1

Please use the equation editor to write the question so we can solve it.

Answer 2

I am new in this site. I don't know what it is..

Answer 3

\[\lim_{n \rightarrow \infty} [(2^{n}+1)(7^{n}+10^{n})]^{\frac{ 1 }{ n }}\]Is that the question?

Answer 4

ya...you are right...Thanks for converting it so..

Answer 5

I can't fully remember, but I know the entire function will approach a certain number as n approaches infinity.

Answer 6

Do you require the answer?

Answer 7

If I remember correctly, remember that \(\sf \color{}{\frac{1}{\infty}=0}\), yes? You can also foil the inside and see what you get: I believe you should get \(\infty\)

Answer 8

No , I am sure the answer is not \[\infty \].

Answer 9

\[= \lim (1+2^{n})^{1/n} * \lim (7^{n} +10^{n})^{1/n}\]
multiply by forms of 1 ... 2/2 and 10/10
\[2\lim (\frac{1+2^{n}}{2^{n}})^{1/n}*10 \lim (\frac{7^{n}+10^{n}}{10^{n}})^{1/n}\]
= 2*10
= 20

Answer 10

the second limit is not equal to 1

Answer 11

http://www.wolframalpha.com/input/?i=lim+%28.7%5En+%2B1%29%5E%281%2Fn%29+as+n+-%3E+infinty

Answer 12

http://www.wolframalpha.com/input/?i=lim+%7B%282%5En+%2B1%29%287%5En+%2B+10%5En+%29%7D%5E%281%2Fn%29+as+n+-%3E+infinty

Answer 13

did you try a ln