Question

PLEASE HELP|!!!!!!! anybody in chemistry A @connexus that did the PHYSICAL AND CHEMICAL CHANGES SEPARATION OF A MIXTURE lab? ANY HELP COUNTS. thanks :D

Answer 1

@Notamathgenius

Answer 2

I go to connections academy too~And i also need lab help, is there any chance your in 8th grade??

Answer 3

no 10th

Answer 4

dang it...um have you been in 8th grade connections academy...?

Answer 5

nah

Answer 6

I can't see the question

Answer 7

whoops sorry i needed help with the 3 questions at the very end

Answer 8

I need help on the Measuring Mass Lab & the Formula of Hydrate Lab...I think I might be able to help you on that lab but have you done these at all??? It's the only things I have left, and then I'll be done with the class for the semester

Answer 9

wat unit is this?

Answer 10

Unit 5 Lessons 9&14

Answer 11

oh no sorry im still in unit 2 :( can u help me?

Answer 12

with what?

Answer 13

some of our things might be different tho

Answer 14

oh i need help wit that portfolio up there ^^ @sarahi_smiles

Answer 15

the lab is at the top up there just click the link @sarahi_smiles

Answer 16

1. In this experiment, what property of NaCl is used to separate it from the other two components? Is this a chemical or physical property?

NaCl is the only compound in this mixture that is soluble in water, so its solubility in water is the property used to separate it. This is a physical property, because you are doing nothing to change the actual chemical composition. It's just solvated by water.

2. In this experiment, what property of CaCO3 is used to separate it from SiO2? Is this a chemical or physical property?

The property of CaCO3 used to seperate it from SiO2 is its reactivity with acetic acid. By adding the acetic acid, you develop carbon dioxide (which bubbles out of solution), and CaCl2, which is soluble in water. You are undergoing a chemical reaction, so this is a chemical property.

3. An unknown sample of a mixture of salt and sand weighs 7.52 g before washing with water and 3.45 g after. What is the percent of sand in the sample? (Show all work.)

7.52g salt and sand, 3.45g sand, 4.07g salt (the difference in before and after water shows how much salt you had)

3.45 g sand / 7.52g total * 100 = 45.9% sand

To check that this is correct, find the percentage of salt as well.

4.07g salt / 7.52g * 100 = 54.1% salt

45.9% + 54.1% = 100%. Everything is accounted for, so this must be the composition of the mixture.

Hope this helped!

Answer 17

Ok yea sorry for being such a dork lol....but I have a modified version of that lab so they are different.. :/ sorry! But I'm sure I can help you in the future with chem...just let me know ok!

Answer 18

ok let me do this one lab and then imma pm u so u can help me ok?