Question

How to solve this?

Answer 1

\[10a ^{2}-20a+8\] Do I need to use the general formula?

Answer 2

solve ? if you want to solve you need an equation (with =0)
do you want to factor this ?

Answer 3

yep

Answer 4

yes what ? factor or solve ?

Answer 5

solve

Answer 6

then yes, you'll need a quadratic formula

Answer 7

Compare your quadratic equation with \(ax^2+bx+c=0\)
find \[a=...?\\b=...?\\c=...?\\\] \[ \\ \sqrt{b^2-4ac}=...?\]
then the two roots of x are:
\(\huge{x_{1,2}=\frac{-b \pm \sqrt{b^2-4ac}}{2a}}\)

Answer 8

\[\frac{ -20\pm4\sqrt{5} }{ 20 }\]

Answer 9

Am I correct until here?

Answer 10

b =-20
right ?
so, -b =+20

Answer 11

Ok...and then?

Answer 12

yeah, then factor out the '4' from the numerator

Answer 13

Thanks! Got it!

Answer 14

welcome ^_^