Question

Please Assist. Using Logs to solve Exponential Equations
See Attachment

Answer 1

Tell me how you proceeded so I can help you.

Answer 2

I'm confused with how to simplify the square root but I believe the other side would become (8x-1) Log 9

Answer 3

That's correct and you can write the first side like this \[(\sqrt{3})^{x+1}=3^{\frac{ x+1 }{ 2 }}\]

Answer 4

okay, thanks. what do I do next?

Answer 5

Your welcome. Now apply log on both sides and find the x.

Answer 6

So would it become 3Log (z+1)-Log 2 = (8x-1) Log 9?

Answer 7

Nope, the rule is \[\log(x ^{a})=a*\log(x)\]

Answer 8

\[\frac{ z+1 }{ 2 } \log 3 \]

Answer 9

Correct

Answer 10

But your variable is x

Answer 11

oh yeah, sorry

Answer 12

I'm not sure on what to do next

Answer 13

well now you got (x+1)/2 log 3 = (8x-1) log 9
So log(3)/2 x +1/2 log(3) = 8 log(9) x -log(9)
Get all the terms that got x on the left and all the others on the right and tell what you got.

Answer 14

im confused..

Answer 15

Do you know what you are looking for ?

Answer 16

x?

Answer 17

Yes, exactly.

Answer 18

log 9 and log 3 are just constants like 8 or (-1) that are gonna help you find your x.

Answer 19

okay thanks

Answer 20

You're welcome