Question

simplify

Answer 1

what are we to simplify?

Answer 2

\[\frac{ e ^{x} e ^{3y} e ^{4z} }{ e ^{\frac{ x }{ x+3y }} }\]

Answer 3

^ that

Answer 4

oops it should be e^(x/2-4y)

Answer 5

For the numerator, you add exponents, since
e^x (e^y) = e^(x+y).

so the numerator is e^(x+3y+4z).

Now you have the numerator (e^(x+3y+4x)) divided by e^ a power.

Now use the other Law of Exponents, that e^x divided by e^y = e^(x-y).

so you will have e^(x+3y+4z) divided by the denominator...just subtract the top exponent - the denominatpr's exponent.

Answer 6

x^2 +3x+4xz -2 +4y?

Answer 7

3xy*

Answer 8

I dont have pen/pencil here. I cant check that last step.

Answer 9

i basically did x(x+3y+4z) -(2-4y)

Answer 10

Doing this in my head, you should get

[(x+3y)(x+3y+4z) - z] / (x+3y).

Answer 11

hmm..

Answer 12

can u show me the steps?

Answer 13

If I read the fraction in the denominator correctly, it reads (z/(x+3y))

Answer 14

o sorry, its x/2-4y

Answer 15

oh, let me do this again

Answer 16

Is that what it says in the denominator of your original question???

Answer 17

yes

Answer 18

I thought it reads e^(z/(x+3y))?

Answer 19

nope its e^(x/(2-4y))

Answer 20

ok..let me see what I get

Answer 21

You should have for a final answer:

e^[(x+3y+4z)(2-4y)-x/(2-4y)]

Answer 22

Only the 2-4y is in the denominator; everything else is in the numerator

Answer 23

how come (2-4y) is in the numerator and denominator?

Answer 24

because you are subtracting 2 fractions..the LCD is (2-4y)

Answer 25

Look at my subtraction of the two fractions. LCD = 2-4y.

Answer 26

o ya.. right.. thx

Answer 27

Welcome.

Answer 28

im sorry but the answer is wrong, i inserted the answer into the program, which asks me the question, and it told me its wrong.

Answer 29

If I read the variables correctly, the answer is correct. If you want to enlarge the problem to make certain that I made no error in any of the variables, feel free to write back.