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Mathematics 13 Online
OpenStudy (anonymous):

tan^2x+tanx=0

OpenStudy (anonymous):

For these types of problems factor them out, since we cant factor completely we can pull out a Tan(x) so we can get, Tan(x) (Tan(x)+1) = 0 now set each of these equal to zero to solve. Tan(x) = 0 Tan(x) +1 =0 Can you get it from here?

OpenStudy (anonymous):

no lol i have no idea what to do with this trig stuff

OpenStudy (anonymous):

that's play it's why we are here. well Tan(x) = 0 that is the first one and the easiest. We need to look at our unit circle and find out where tan(x) is = to 0 which if you look is anywhere where sin(x) is =0 so , 0 and pi For tan(x) +1= 0 well make Tan(x) =-1 and do the same thing well again looking at the unit circle we know that anywhere pi/4 tan(x) is =1 follow me so far?

OpenStudy (anonymous):

okay*

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

so tan= -1 would just be pi?

OpenStudy (anonymous):

actually no 3pi/2

OpenStudy (anonymous):

no not quite, if we know that pi/4 is either 1, -1 its going to be either pi/4 3pi/4 5pi/4 or 7pi/4

OpenStudy (anonymous):

its going to be some variation of pi/4 because tangent is sine over cosine, for tangent to be 1, cosine and sine need to be equal which occurs at pi/4, 3pi/4, 5pi/4 and 7pi/4

OpenStudy (anonymous):

well we know, quadrant 1 coordinates are (+,+) so tangent would be +/+ = + so its not in quadrant 1 quadrant 2 coordinates are (-,+) which if we do tangent is +/- = - so quadrant 2 is valid quadrant 3 is (-,-) so -/- = +so quadrant 3 cant be it quadrant 4 is (+,-) so a -/+ = a - so for tangent of x to be a -1 it has to be in quadrant 2 and 4 to be negative and a pi/4 variation to be a one

OpenStudy (anonymous):

so we find the pi/4 in quadrant 2 and 4 and the answer should be 3pi/4 and 7pi/4 along with your earlier answers of 0 and pi Answers: (0,3pi/4,pi,7pi/4)

OpenStudy (anonymous):

these ansers dont have to be added to Kpi?

OpenStudy (anonymous):

it depends on the question if it says for the interval [0,2pi] then no, but if it says all values then yes just put all of them in parentheses and put +2kpi

OpenStudy (anonymous):

yes its {0, 2pi] thanks for your help!

OpenStudy (anonymous):

yep!

OpenStudy (anonymous):

i have 2 other questions that im stumped on if you can help

OpenStudy (anonymous):

sin2x-sinx+2cosx-1=0

OpenStudy (anonymous):

sin2x-sinx+2cos=1

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