Using limits to find the slant asymptote for (x-2)^2/(x+3)
Asymptote: y=ax+b
Finding a:
Lim x--> + infinity f(x)/x=a
What is the equation for finding b?
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OpenStudy (anonymous):
um well u can find the slant asymptote just but using long division, with limits we can expand the numerator first
OpenStudy (anonymous):
How would you do this using limits? (sorry, my teacher required us to do this with limits!)
OpenStudy (anonymous):
alright lets try this
OpenStudy (anonymous):
expand the numerator first
OpenStudy (anonymous):
(x^2-4x+4)/(x^2+3x)
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OpenStudy (anonymous):
now divide the function by x
OpenStudy (anonymous):
I mean over x+3!
OpenStudy (anonymous):
you are a step ahead of me haha
OpenStudy (anonymous):
now divide the numerator and denominator by the highest power (x^2)
OpenStudy (anonymous):
so a=1
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OpenStudy (anonymous):
yep
OpenStudy (anonymous):
but what would b =?
OpenStudy (anonymous):
because the slant asymptote is y=ax+b
a=1
so y=x+b
OpenStudy (anonymous):
to find b you can only use long division...
OpenStudy (anonymous):
no limits are involved in finding b, only a
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OpenStudy (anonymous):
Ok thank you for your help!
OpenStudy (anonymous):
hold up!
OpenStudy (anonymous):
do division first and tell me what you get
OpenStudy (anonymous):
x-7?
OpenStudy (anonymous):
now b = lim [Quotient - mx]
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