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Mathematics 16 Online
OpenStudy (anonymous):

Using limits to find the slant asymptote for (x-2)^2/(x+3) Asymptote: y=ax+b Finding a: Lim x--> + infinity f(x)/x=a What is the equation for finding b?

OpenStudy (anonymous):

um well u can find the slant asymptote just but using long division, with limits we can expand the numerator first

OpenStudy (anonymous):

How would you do this using limits? (sorry, my teacher required us to do this with limits!)

OpenStudy (anonymous):

alright lets try this

OpenStudy (anonymous):

expand the numerator first

OpenStudy (anonymous):

(x^2-4x+4)/(x^2+3x)

OpenStudy (anonymous):

now divide the function by x

OpenStudy (anonymous):

I mean over x+3!

OpenStudy (anonymous):

you are a step ahead of me haha

OpenStudy (anonymous):

now divide the numerator and denominator by the highest power (x^2)

OpenStudy (anonymous):

so a=1

OpenStudy (anonymous):

yep

OpenStudy (anonymous):

but what would b =?

OpenStudy (anonymous):

because the slant asymptote is y=ax+b a=1 so y=x+b

OpenStudy (anonymous):

to find b you can only use long division...

OpenStudy (anonymous):

no limits are involved in finding b, only a

OpenStudy (anonymous):

Ok thank you for your help!

OpenStudy (anonymous):

hold up!

OpenStudy (anonymous):

do division first and tell me what you get

OpenStudy (anonymous):

x-7?

OpenStudy (anonymous):

now b = lim [Quotient - mx]

OpenStudy (anonymous):

|dw:1384164890097:dw|

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