Question

Differentiate h(theta)=5 theta sec theta

Answer 1

its a product rule ...

h = 5x sec(x)

Answer 2

so would that sec(x) become a sec(x)tan(x)

Answer 3

yes

Answer 4

swell.

Answer 5

h = 5x sec(x)

h' = 5x' sec(x) + 5x sec(x)'

h' = 5sec(x) + 5x sec(x)tan(x)

h' = 5sec(x) (1+x tan(x))

or however you want to present it :)

Answer 6

thanks a bunch!

Answer 7

How did you get the one in "(1+x tan(x))"?

Answer 8

i factored out a common factor ...

Answer 9

5sec(x) + 5x sec(x)tan(x)

let a = 5 sec(x)

a + a xtan(x)

factor out the a

a (1+ x tan(x))

Answer 10

I think I'm understanding that now...thanks again! :)