Complete the square and write the equation in standard form. Then give the center and radius of the circle.

x2 + y2 - 10x - 8y + 29 = 0

Question

Complete the square and write the equation in standard form. Then give the center and radius of the circle. 

x2 + y2 - 10x - 8y + 29 = 0

myininaya · Answer

$$(x^2-10x)+(y^2-8y)=-29 $$
$$(x^2-10x+?_1)+(y^2-8y+?_2)=-29+?_1+?_2 $$
We need to figure out what those ?'s should be

myininaya · Answer

To complete the square we do $$x^2 \pm kx+ (\frac{k}{2})^2=(x \pm \frac{k}{2})^2 $$

myininaya · Answer

$$y^2\pm ky+(\frac{k}{2})^2=(y \pm \frac{k}{2})^2$$

myininaya · Answer

So take the number in front of x and then divide it by 2 
then square that result that will be ?_1

yacoub1993 · Answer

Q. what does k stand for cause in the equation i gave there is no k

myininaya · Answer

$$x^2-10x+?_1 $$
$$x^2-kx+(\frac{k}{2})^2$$

myininaya · Answer

do you see what k is now?

myininaya · Answer

I'm giving you a formula for completing the square
I'm trying to get you to identify what k is in the expression I just wrote.

myininaya · Answer

What is in front of x in both expressions?

myininaya · Answer

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