no +ve integer x & y such that, x^2 - 3xy + 2y^2 = 10
not sure what the exact question is, but it seems like you need to factor it:\[\large (x -2y)(x-y) = 10\]now each of the brackets must be factors of 10 (since i'm assuming they're only allowing integers)
eg one bracket must be equal to 1, the other must be equal to 10 or one is equal to 2, and the other 5 those are the only factors of 10. You can use them to make simultaneous equations.
Prove or disprove there are no positive integers x and y such that; \[x^2 -3xy+2y^2=10\]
Not sure how to do it through induction.
x-2y = 10 and x-y = 1 or x-2y = 1 and x-y = 10 or x-2y = 5 and x-y = 2 or x-2y = 2 and x-y = 5 with those you can prove it and it won't take long.
If there are any positive integers, those will find them.
cheers mate
oh, actually, you'd also need to check for cases when both factors are -ve... ie -1 and -10, and -2 and -5
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