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Chemistry 14 Online
OpenStudy (anonymous):

If 12.8 grams of iron (III) oxide reacts with 11.5 grams of carbon monoxide to produce 6.10 g of pure iron, what are the theoretical yield and percent yield of this reaction? Be sure to show the work that you did to solve this problem. (4 points) unbalanced equation: Fe2O3 + CO yields Fe + CO2

OpenStudy (anonymous):

@abb0t helppp! please :)

OpenStudy (abb0t):

\(\sf \color{}{Fe_2O_3 + CO \rightarrow Fe + CO_2}\) now, you need to start by balancing this. Do you know how to balance?

OpenStudy (anonymous):

Fe2O3 + 3 CO = 2 Fe + 3 CO2 is that correct?

OpenStudy (abb0t):

Yes, that is correct. Good job.

OpenStudy (anonymous):

Cool :)

OpenStudy (abb0t):

Now find the mass of each and convert to the products, which is CO\(_2\). you are essentially trying to find out how much of each you would theoretically produce with the given amounts

OpenStudy (abb0t):

So, convert 12.8 grams of Fe\(_2\)O\(_3\) and 11.5 grams of CO to Fe and CO\(_2\).

OpenStudy (abb0t):

aRE You familiar with how to convert to iron and carbon dioxide? Meaning, use of dimensional analysis.

OpenStudy (anonymous):

Fe2O3 = 12.8 g / 159.694 g / mol = 0.0802

OpenStudy (anonymous):

No.. This is not a practice exam. This is a module quiz from FLVS so using this answer will be an academic integrity violation. Plus it has a obvious mistake in it. Mr. Carlyle FLVS Chemistry Instructor This question is a violation of the OpenStudy Guidelines. The question is from an online school plus a violation by solicitation for members to unknowingly assist them cheating on an exam. 30653065chem30653065

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