Question

Evaluate the following expression using the values given:

1. ) Find -a2 - 3b3 + c2 + 2b3 - c2 if a = 3, b = 2, and c = -3.

-67

-17

-31

1



(01.02)



2. ) Find x - 3y if x = 3 and y = -2.

-9

-3

3

9

Answer 1

you are given this equation:
-a^2 - 3b^3 + c^2 + 2b^3 - c^2
every where 'a' appears, put a (3) because of this equation, a = 3.
every where 'b' appears, put a (2) because of this equation, b = 2, and
every where 'c' appears, put a (-3) because of this equation, c = -3

Answer 2

you are given this equation:
x - 3y
Every time you see an 'x', replace it with a (3) becuase of this, x = 3 and
every time you see a 'y', replaces it with a (-2) becuase of this, y = -2

Answer 3

Would # 2 be -9 ?

Answer 4

close, so we have:
x - 3y
3 - 3(-2)
3 - (-6)
3 + 6
see where you went wrong?

Answer 5

So it's positive 9

Answer 6

yep ^_^

Answer 7

And would # 1 be -17 ?

Answer 8

Nevermind - 31 ?

Answer 9

@DemolisionWolf

Answer 10

is this what you had?
-(3)^2 - 3(2)^3 + (-3)^2 + 2(2)^3 - (-3)^2

Answer 11

Find -a2 - 3b3 + c2 + 2b3 - c2 if a = 3, b = 2, and c = -3.

Answer 12

right, but after you replaces all the a's, b's and c's with the numbers, did yours look like mine?

Answer 13

Afterwords it looked like this : -5-8+5+7-5 = -31

Answer 14

is should look like:
-(3)^2 - 3(2)^3 + (-3)^2 + 2(2)^3 - (-3)^2
-9 - 24 + 9 + 16 - 9

Answer 15

Thanks