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Find all real zeros of the function y=x^3 - 4 x^2 - 9 x +36. Give your answer as a comma separated list. If there are no real zeros, type none . The real zeros are x=
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-3, 3, 4
Thank you!
You are welcome! I used my graphing calculator to graph the equation. It has 3 zeros, which is one for each term, x^(n).
do you know how to do it without a calculator?
Yes, for expressions like this you need to try to plug in small whole numbers like 1,2,3,4 etc. It's a lot of guess work. In the equation, the coefficients are 1, -4, 9, and 36. Those are all perfect squares, so you see right away that the square root of these, or combination of the square roots of these may be solutions. So try -2, 3, 6 too
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alright thank you. i will try!
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