Question

Simplify each product. Write in standard form.

Answer 1

@♪Chibiterasu

Answer 2

\[3r-2^{2}\]

Answer 3

honestly i think u just do the 2^2 and done? xD Honestly like
\[3r-4\]
Does this make sense hold up lemme get chibi in here

Answer 4

@♪Chibiterasu

Answer 5

ughh x.x hes helping with another problem

Answer 6

So I would just do the problem like a regular equation?

Answer 7

i think so cuz it asks for standard form

Answer 8

Ok

Answer 9

does it tell u if u were wrong?

Answer 10

\[(3r-2)^{2}\]

Answer 11

Its not a test.
Its an assignment that I have to turn in

Answer 12

Ahhh

Answer 13

@♪Chibiterasu

Answer 14

i need corrected if im wrong its been awhile

Answer 15

that was right 3r-4

Answer 16

Oh it was? OK C:

Answer 17

What about this one:
(7q+2)(3q+8)

Answer 18

U would combine like terms

Answer 19

what is the problem

Answer 20

Squaring a number is the same as multiplying the number by itself (2*). In this case 2 squared is 4.

Answer 21

but like i forget how to do that

Answer 22

(7q+2)(3q+8) ??

Answer 23

I didn't get notified of the mention for some reason.

Answer 24

ok binks :) thx for that refresher

Answer 25

7q(3q+8)+2(3q+8)
21q^2+56q+6q+16
21q^2+62q+16

Answer 26

(3r−2)^2
(3r-2)(3r-2)
3r(3r-2)-2(3r-2)
9r^2-6q-6q+4
9r^2-12q+4

Answer 27

Notice how the squared coefficient is not combined, so they are like terms due to the fact that they are raised to different powers.

Answer 28

I have 3 more if anyone woudnt mind helping with c:

Answer 29

ill give it a shot c:

Answer 30

i need one more ss score c:

Answer 31

Wait wrong one

Answer 32

Its like the same thing c: Combine like terms

Answer 33

yes.

Answer 34

Ok I think I got the rest any ways thanks

Answer 35

Yupp :)

Answer 36

The problem to solve is:
(7h-3)(7h-3)

Multiply h and 7
Multiply h and 1


The h just gets copied along.

The answer is h

h

7*h evaluates to 7h

7*h-3 evaluates to 7h-3

Multiply h and 7

Multiply h and 1


The h just gets copied along.

The answer is h

h

7*h evaluates to 7h

7*h-3 evaluates to 7h-3

Multiplying 7h-3 by 7h-3 is a classic Algebra problem. Here, you are trying
to multiply two binomials together (two expressions that each contain two terms).
Your book might call this finding the "Product of Two Binomials".

To work this problem, we'll use the "F.O.I.L." method. F.O.I.L. stands
for First, Outer, Inner, Last.

First, we'll multiply the two First terms, the 7h and 7h together.

Multiply 7h and 7h

Multiply the h and h

Multiply h and h


Combine the h and h by adding the exponents, and keeping the h, to get

The answer is



7h × 7h =

Second, we'll multiply the two Outer terms, the 7h and -3 together.

Multiply 7h and -3

Multiply h and 1


The h just gets copied along.

The answer is h

h

7h × -3 = -21h

Third, we'll multiply the two Inner terms, the -3 and 7h together.

Multiply -3 and 7h

Multiply 1 and h


The h just gets copied along.

h

-3 × 7h = -21h

-21h combines with -21h to give -42h

Lastly, we'll multiply the two Last terms, the -3 and -3 together.

Multiply -3 and -3


1

-3 × -3 = 9

(7*h-3)*(7*h-3) evaluates to

Answer 37

Whoa Udit O.O LOL

Answer 38

It was actually (7h-3)(7h+3)

Answer 39

49h^2-42h+9

Answer 40

OMgggg

Answer 41

LOLOL

Answer 42

The problem to solve is:
(7h-3)(7h+3)

Multiply h and 7
Multiply h and 1


The h just gets copied along.

The answer is h

h

7*h evaluates to 7h

7*h-3 evaluates to 7h-3

Multiply h and 7

Multiply h and 1


The h just gets copied along.

The answer is h

h

7*h evaluates to 7h

7*h+3 evaluates to 7h+3

Multiplying 7h-3 by 7h+3 is a classic Algebra problem. Here, you are trying
to multiply two binomials together (two expressions that each contain two terms).
Your book might call this finding the "Product of Two Binomials".

To work this problem, we'll use the "F.O.I.L." method. F.O.I.L. stands
for First, Outer, Inner, Last.

First, we'll multiply the two First terms, the 7h and 7h together.

Multiply 7h and 7h

Multiply the h and h

Multiply h and h


Combine the h and h by adding the exponents, and keeping the h, to get

The answer is



7h × 7h =

Second, we'll multiply the two Outer terms, the 7h and 3 together.

Multiply 7h and 3

Multiply h and 1


The h just gets copied along.

The answer is h

h

7h × 3 = 21h

Third, we'll multiply the two Inner terms, the -3 and 7h together.

Multiply -3 and 7h

Multiply 1 and h


The h just gets copied along.

h

-3 × 7h = -21h

21h combines with -21h to give 0h

Lastly, we'll multiply the two Last terms, the -3 and 3 together.

Multiply -3 and 3


1

-3 × 3 = -9

(7*h-3)*(7*h+3) evaluates to 49h^2-9

Answer 43

Woah. You type fast

Answer 44

Thank you, again.

Answer 45

Welcome my pleasure