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prove the identity 1- cos^2theta/1+sin theta =sin theta help plzz :)
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\[\frac{ 1-\cos^2\theta }{1+\sin \theta }=\sin \theta\] like this?
no |dw:1384227325672:dw|
\[1-\frac{ \cos^2\theta }{ 1+\sin \theta }=1-\frac{ 1-\sin^2\theta }{ 1+\sin \theta }=1-\frac{ (1-\sin \theta)(1+\sin \theta) }{ 1+\sin \theta }\] you should be able to finish it from there...
more help plz
dude... seriously?
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so it wel be \[1- 1/1+\sin \]
cancel the common terms
\[1-\frac{ (1-\sin \theta)\cancel{(1+\sin \theta)} }{ \cancel{(1+\sin \theta)} }=1-(1-\sin \theta)\]
thanks :)
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