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Mathematics 18 Online
OpenStudy (anonymous):

u=20i+25j use dot product to find the magnitude

OpenStudy (anonymous):

i don't understand where the i and j go or what they are?

OpenStudy (isaiah.feynman):

Well the dot product is used when you have TWO vectors, you only have one vector. To find the magnitude of a vector use the following formula. \[u=\sqrt{x^{2}+y^{2}} \] In where x and y are the components of the vector. @noen10 i and j are unit vectors of magnitude 1 they point towards the direction of the x and y axis respectively.

OpenStudy (anonymous):

okay well the book only gave me one, I'm not sure how to get it from here? @Isaiah.Feynman

OpenStudy (anonymous):

the i's and j's really mess with me. would i just solve them normally?

OpenStudy (isaiah.feynman):

Yes just solve them normally. i and j have magnitude one, one times a number is still that number.

OpenStudy (anonymous):

oh haha thanks, man that was messing me up.

OpenStudy (anonymous):

@Isaiah.Feynman how do i find the magnitude of u=<3,4> and magnitude of v=<0,-2>

OpenStudy (anonymous):

would it just be \[\sqrt{3^{2}+4^{2}}\]

OpenStudy (anonymous):

for u?

OpenStudy (isaiah.feynman):

Yes.

OpenStudy (anonymous):

@Isaiah.Feynman determine if u and v are orthogonal u=<3,15> v=<-1,5>

OpenStudy (anonymous):

orthogonal, neither or parallel. i know its not orthogonal but how do i figure out if it is parallel slope?

OpenStudy (isaiah.feynman):

Two vectors are orthogonal if they form 90 degrees with each other which means their dot product is zero.

OpenStudy (isaiah.feynman):

Parallel slope? never heard of that.

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