Question

Write an equation of a line in point-slope form that has a slope of -2 and passes through (5, -1).

Answer 1

so far you know that it is hoing to be y=-2x+b
slope is -2, however "b" or the y-intercept is unknown.
Plug in your point (5, -1) into y=-2x+b
--->
(-1)=-2(5)+b
-1=-10+b
add 10 to both sides.
-1+10=-10+b+10
9=b
so knowing that b=9 and slope=-2, YOU GET---->
y=-2x+9


Good?

Answer 2

Wasn't one of the answers :o
A. y + 1 = -2(x – 5)
B. y – 1 = -2(x – 5)
C. y – 5 = -2(x + 1)
D. y -5 = -2(x – 1)

Those are the answers

Answer 3

oh, in point slope from.... then A.

Answer 4

y=-2x+9 add 1 to both sides
y+1=-2x+10

Answer 5

Thanks

Answer 6

Anytime!