Could someone explain this to me pleasee
what do you need explained?
\[2 \frac{ 1 }{ 6 } + d = 1 \frac{ 1 }{ 9 }\]
sorry I can't help cause I have to go. But I hope someone else can! :) @swami @hba @J-Cross18
Okay, thanks though @Gatorgirl :)
I can help. :3 hold on, I'll start doing it for you now.
Okay thanks! :)
\[2\frac{ 1 }{ 6 } + d = 1\frac{ 1}{9 }\] First off, we need to make the denominators the same (it makes it a lot easier.) The smallest common denominator would be 18 (6*3=18 & 2*9=18) so in order to make the fractions equal, you must multiply them with whatever was the number you multiply it by to make it equal to the smallest common denominator. So 2 1/6 would be 2 3/18 and 1 1/9 would be 1 2/18. \[2 \frac{ 3 }{ 18 } + d = 1\frac{ 2 }{ 18 }\] in order to get d by itself, we have to subtract the 2 3/18. This is easier to do now that they have the same denominator. However, we should make them improper fractions. |dw:1384294816932:dw| You would multiply the bottom number (18) times the number on the left (2) and then add the 3. This would give you the improper fraction of 39/18. You should do the same on the other side. |dw:1384294902353:dw| (18*1) +2= 20/18. Now we are ready to actually get d. \[\frac{ 39 }{18 } + d = \frac{ 20 }{ 18 }\] Because the denominators are the same, we can just subtract the 39 from the 20, and put it over 18. \[\frac{ 39 }{ 18 } + d - \frac{ 39 }{ 18 }= \frac{ 20 }{ 18 } - \frac{ 39 }{ 18 }\] \[\frac{ 20 }{ 18 } - \frac{ 39 }{ 18 } = -\frac{ 19 }{ 18 }\] Now we can check to see if this works. \[\frac{ 39 }{ 18 } + -\frac{ 19 }{ 18 } = \frac{ 20 }{ 18 }\]
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