Question

simplify √27x^5 √3x^3

Answer 1

what is a common number found in each discriminent? we have a 27x^5 and a 3x^3, what can you factor out?

Answer 2

\(\bf \large \sqrt{27}x^5\times \sqrt{3}x^3\quad ?\)

Answer 3

yes how do you simplify that

Answer 4

\(\bf \sqrt{27}x^5\times \sqrt{3}x^3\implies \sqrt{27\times 3}x^5x^3\) and as you recall from the rules of exponents, same base, you add the exponents, thus \(\bf \sqrt{27}x^5\times \sqrt{3}x^3\implies \sqrt{27\times 3}x^5x^3\implies \sqrt{27\times 3}x^{5+3}\)

Answer 5

would it be x√3x 3times2x√3x?

Answer 6

\[x \sqrt{3x}\] \[3\times2x \sqrt{3x}\]

Answer 7

hmmm \(\bf \large \sqrt{27}x^5\times \sqrt{3}x^3\) has the "x" variables outside the radical

Answer 8

the x^5 and x^3 are both in the square root

Answer 9

is it like this?