simplify √27x^5 √3x^3

Question

anonymous · Answer

what is a common number found in each discriminent? we have a 27x^5 and a 3x^3, what can you factor out?

jdoe0001 · Answer

$\bf \large \sqrt{27}x^5\times \sqrt{3}x^3\quad ?$

anonymous · Answer

yes how do you simplify that

jdoe0001 · Answer

$\bf \sqrt{27}x^5\times \sqrt{3}x^3\implies \sqrt{27\times 3}x^5x^3$   and as you recall from the rules of exponents, same base, you add the exponents, thus $\bf \sqrt{27}x^5\times \sqrt{3}x^3\implies \sqrt{27\times 3}x^5x^3\implies \sqrt{27\times 3}x^{5+3}$

anonymous · Answer

would it be x√3x 3times2x√3x?

anonymous · Answer

$$x \sqrt{3x}$$ $$3\times2x \sqrt{3x}$$

jdoe0001 · Answer

hmmm    $\bf \large \sqrt{27}x^5\times \sqrt{3}x^3$    has the "x" variables outside the radical

anonymous · Answer

the x^5 and x^3 are both in the square root

anonymous · Answer

is it like this?
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