Theorem: The diagonals of a parallelogram bisect each other. Kim is writing the proof of the theorem using two properties of a parallelogram as shown below. • The opposite sides of a parallelogram are parallel. • The opposite sides of a parallelogram are congruent. A parallelogram ABCD with diagonals AC and BD intersecting at G. Using the two given properties, Kim proved that triangle AGB is congruent to triangle CGD using the ASA Postulate.
What theorem can Kim use to prove that segment AG is congruent to segment CG, and that segment BG is congruent to segment DG to show that the
please help @jim_thompson5910
it says she "proved that triangle AGB is congruent to triangle CGD using the ASA Postulate"
so how can you use this to show that AG = CG
by asa i think
that part is already done
what theorem allows you to go from saying if two triangles are congruent, then the pieces must be congruent
im not sure
hint: starts with a C
corresponding sides are congruent?
close, CP____ (fill in the rest)
cpctcp something like this
CPCTC, yep CPCTC = corresponding parts of congruent triangles are congruent
basically in a nutshell: if the whole triangles are congruent, then the pieces that match up are congruent (sides and angles)
wait the last part of the question didnt show it said What theorem can Kim use to prove that segment AG is congruent to segment CG, and that segment BG is congruent to segment DG to show that the diagonals bisect each other?
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