Help Please!! A block of brass of mass 500 gram and temperature 100C is placed in 300 grams of water at 20C which is in an aluminium calometer of mass 75 grams. If the final temperature is 30C calculate the specific heat of brass? Cwater = 4200J/kg/C Calum= 880J/kg/C
From newton's heat transfer we know that mCpdT=constant for all three bodies. This basically says that q=constant through the system. So what type of equation can you set up after knowing this?
where m=mass, Cp=specific heat, and dT=temp change
heat loss from brass = heat gained by aluminium + heat gained by water
i was trying mCdT of brass = mCdT of alimunium + mCdT of water 9 but maybe i should have subtracted)
Very good young sir
omit 9
haha neither young nor a sir but thanks :D young man
for the final temp of the Brass do I use the 20C or the 30C ?
It says the final bulk temp of brass is 30. Use 30 for brass. The 20 is for the water
Also make sure to use kg not grams. Bc the Cp values are in a kg basis
so dont use 500 grams or 300 grams use .5kg or .3kg
ok so for the Brass .5 * C * (30-100)
water is .3 * 4200 * (30-20)
and Aluminium is .075 * 880 * (30-20)
im lost here... I am not getting 3770 which is the C of brass
Yep and I got about 378J/kgK which is very close to the listed value of about 380 J/kgK
Not sure where you get 3770? A good reference is here http://www.engineeringtoolbox.com/specific-heat-metal-alloys-d_153.html which lists about 380
my book has a list... hmm ok ill check it out
my book lists it as J/kg/C
but im confused as I used 4200 and 880 which is J/kg/C why don't i get the 3770 j/kg/C :S
Has to be a typo. That value does not even make sense. The heat capacities of solid metals are usually low, under 500 J/kgK
specific heats* not capacities
The method we did is correct. You get a negative value at the end because the brass is losing heat, so q is negative.
ok so i write it as J/kg/K ? i'll attach the table shown in my book
that's why i was expecting the 3770 lol i don't think i fully understand this topic yet.
Bro i would not get too worked up about it. We did the math, and our answer is about 380. All other references show 380. http://www.diracdelta.co.uk/science/source/s/p/specific%20heat%20capacity/source.html#.UoLdLeL-Upc
Yet another trusted referenc ehsowing 370 J/kgK
alrighty thanks so much for your help i trust a chem engineer hahah
Indeed you should, as i spent an entire year studying heat transfer! Anytime man...
cheers braaaaah
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