4.80 mol of solid A was placed in a sealed 1.00-L container and allowed to decompose into gaseous B and C. The concentration of B steadily increased until it reached 1.30 M, where it remained constant.

A(s) --B(g) + C(g)

Then, the container volume was doubled and equilibrium was re-established. How many moles of A remain?

Question

4.80 mol of solid A was placed in a sealed 1.00-L container and allowed to decompose into gaseous B and C. The concentration of B steadily increased until it reached 1.30 M, where it remained constant.

A(s) -->B(g) + C(g)

Then, the container volume was doubled and equilibrium was re-established. How many moles of A remain?

anonymous · Answer

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