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Mathematics 24 Online
OpenStudy (anonymous):

Jane is 7 years older than amy. twelve years ago, amy was half as old as jane is now. ow old is jane now?

OpenStudy (anonymous):

OK, yes i understand

OpenStudy (anonymous):

How would i do that?

terenzreignz (terenzreignz):

None of them could possibly be 7 years old now... or else 12 years ago, their age would be negative -_- Absurd.

terenzreignz (terenzreignz):

Granted. Your final answers are Jane = 26 Amy = 19 then?

terenzreignz (terenzreignz):

Okay, well it's wrong. Twelve years ago, Amy was half as old as Jane is *now*.

OpenStudy (anonymous):

it says 12 years ago amy was half as old as jane is now, and 7 isnt half of 26?

terenzreignz (terenzreignz):

^agreed. So far you've given two wrong answers in a row, Zelman. Let me handle this, for the sake of humanity :>

terenzreignz (terenzreignz):

Okay.... @Wherewillweland Listen up. We're looking for Jane's age NOW, so we let that be x. You follow?

OpenStudy (anonymous):

ok so far so good

terenzreignz (terenzreignz):

If Jane's age NOW is x, then what's Amy's age NOW? (HINT: Jane is 7 years older.)

OpenStudy (anonymous):

x-7

terenzreignz (terenzreignz):

That's good. Since Amy is x-7 years old NOW, 12 year ago, what would be her age?

OpenStudy (anonymous):

x-19?

terenzreignz (terenzreignz):

That is correct, and this is equal to HALF of Jane's age NOW, which is x. Therefore\[\Large x- 19 = \frac12x\] Solve for x, you'll get Jane's age.

OpenStudy (anonymous):

I think i did something wrong because i got 9.5

terenzreignz (terenzreignz):

If you're confused, try multiplying both sides of the equation by 2. \[\Large 2x - 38 = x\]

OpenStudy (anonymous):

So the answer is 38?

terenzreignz (terenzreignz):

That is correct :) Notice that if Jane is 38 now, Amy is 31 now. 12 years ago, Amy would be 31-12, or 19, which IS half of Jane's age now. Well done ^_^

OpenStudy (anonymous):

Awesome! thanks so much for your help

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