Question

Suppose that a polynomial function of degree 5 with rational coefficients has 2, √3, and 5+2i as zeros. Find the other zeros.

Answer 1

one is 5-2i

Answer 2

hint : irrational roots occur in conjugate pairs

Answer 3

if \(a+\sqrt{b}\) is a zero, then \(a-\sqrt{b}\) will also be a zero

Answer 4

so what does it mean @sara12345

Answer 5

you're given a irrational root right ?

Answer 6

since \(\sqrt{3}\) is a zero, \(-\sqrt{3}\) will also be a zero

Answer 7

so how many zeroes did you get so far ?

Answer 8

i really don't know...teacher just taught the lesson today...

Answer 9

its okay,
im asking how many zeroes *we* got so far :)

Answer 10

in the question we're already given 3 zeroes : \(2, \sqrt{3} , 5+2i\)
we found one more zero : \(-\sqrt{3}\)

Answer 11

so total, 4 zeroes we have so far

Answer 12

since its a 5 degree polynomial, there will be one more zero which we need to find okj

Answer 13

alright thanks

Answer 14

np :) you found the 5th zero also ?

Answer 15

oh 5-2i

Answer 16

Yes ! 5 degree polynomial will have 5 zeroes. so we're done :)

Answer 17

thanks

Answer 18

np :)