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Medal given factorize x^2 - 49
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x-7 x+7
(x+7)(X-7)
can you have 1(x^2-49)
@cassytaylor92
@hartnn
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1 is the factor of every expression, so we need not mention the '1' there. also, x^2-49 was still unfactorized there, right ?
so, it would be right?
for \(a^2-b^2 = (a+b)(a-b)\) so for \(x^2-7^2= (x+7)(x-7)\)
so, it would not be right?
so, 1(x^2-49) is not right and (x+7)(x-7) is correct
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ok
so, how would you do, x^2-16=4x
you want to solve that ? you know the quadratic formula ?
quadratic formula
you know what it is ?
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yes
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